Question

How many milliliters of a 1.5 m h2so4 are needed to neutralize 35ml sample of a 1.5 m solution?

1) 17.5ml


2) 35ml


3) 52.5ml


4) 3.0ml

Answer 1

1) 17.5 mL

Step-by-step explanation:

Hello,

In this case, the reaction between sulfuric acid and potassium hydroxide is:

`H_2SO_4+2KOH\rightarrow K_2SO_4+2H_2O`

In such a way, we notice a 1:2 molar ratio between the acid and the base, therefore, at the equivalence point we have:

`2*n_(acid)=n_(base)`

And in terms of concentrations and volumes:

`2*M_(acid)V_(acid)=M_(base)V_(base)`

Thus, we solve for the volume of acid:

`V_(acid)=(M_(base)V_(base))/(2*M_(acid)) =(35mL*1.5M)/(2*1.5M) \\\\V_(acid)=17.5mL`

Best regards.