Answer: The numbers are: 16, 11 and 48
Explanation:
Let 1st number is a, second number is b and third number is c
1st number is 5 more than the second so a=b+5
The third number is 2 times the first so c=3*a=3*(b+5)
The sum of three numbers, so a+b+c=b+5+b+3*(b+5)=75
b+5+b+3+3b+15=75
5b+20=75
5b=55
b=11
a=b+5=11+5=16
c=3*(b+5)=3*(11+5)=3*16=48
The numbers are: 16, 11 and 48