Question

Tanya has several bills in her wallet. She has a total of $40. If she has one more $5 bill than $10 bills, and two more $1 bills than $5 bills, how many of each does she have?

Answer 1

Tanya has 2 $10 bills, 3 $5 bills, and 5 $1 bills in her wallet.

Step-by-step explanation:

To solve this problem, we can set up a system of equations. Let's denote the number of $10 bills Tanya has as 'x'. Since she has one more $5 bill than $10 bills, the number of $5 bills she has would be 'x + 1'. Similarly, the number of $1 bills she has would be 'x + 1 + 2', or 'x + 3'.

Now, we can write the equation for the total amount of money in Tanya's wallet:

10x + 5(x + 1) + 1(x + 3) = 40

Simplifying this equation, we get:

10x + 5x + 5 + x + 3 = 40

Combining like terms, we have:

16x + 8 = 40

Subtracting 8 from both sides, we get:

16x = 32

Dividing both sides by 16, we find that:

x = 2

Therefore, Tanya has 2 $10 bills, 3 $5 bills, and 5 $1 bills in her wallet.