Question

One way to cool a gas is to let it expand. When a certain gas under a pressure of 5.00 x 10^6 Pa at 25.°C is allowed to expand to 3 times its original

volume, its final pressure is 1.07 x 10^6 Pa. What is its final temperature:​

Answer 1

The final temperature is T2= 5.35°C

Step-by-step explanation:

Apply the Gay-lussacs's law we have

`(P1)/(T1) = (P2)/(T2)`

P1, initial pressure= 5.00 x 10^6 Pa

T1, initiation temperature= 25.°C

P2, final pressure= 1.07 x 10^6 Pa

T2, final temperature= ?

`(5.00 * 10^6)/(25) =(1.07 *10^6)/(T2) \\`

Cross multiplying and making T2 subject of formula we have

`T2 =(1.07 *10^6*25)/(5.00 * 10^6) \\\\T2= (26.75)/(5) \\T2= 5.35`

T2= 5.35°C