Question

Find the 24th term of an arithmetic sequence for which a_1 = 2 and d = 6.

Answer 1

140

Explanation:

The n th term of an arithmetic sequence is

`a_(n)` = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 2 and d = 6 , thus

`a_(24)` = 2 + (23 × 6) = 2 + 138 = 140

Answer 2

Answer: a₂₄ = 140

Explanation:

The formula for an arithmetic sequence is:
`a_n=a_1+d(n-1)` where

• a₁ is the first term of the sequence
• d is the difference between terms
• n is the term you are looking for

Given: a₁ = 2, d = 6, n = 24

a₂₄ = 2 + 6(24 - 1)

= 2 + 6(23)

= 2 + 138

= 140

The 24th term is 140.