Question

I need help please!!!!!

Answer 1

48 ft^3

Solution,

`b = 6 \: ft \\ h = \sqrt{ {5}^(2) - {3}^(2) } \\ \: \: \: \: \: = √(25 - 9) \\ \: \: \: \: \: = √(16) \\ \: \: = \sqrt{ {4}^(2) } \\ \: \: \: \: = 4`

Now,

`volume = (1)/(3) bh \\ \: \: \: \: \: \: \: \: \: \: \: = (1)/(3) * {6}^(2) * 4 \\ \: \: \: \: \: \: \: \: \: \: = (1)/(3) * 36 * 4 \\ \: \: \: \: \: \: \: \: \: \: \: = 48 \: {ft}^(3)`

hope this helps...

Good luck on your assignment..

Answer 2

Volume = 48 ft³

Explanation:

Finding h first by Pythagorean Theorem:

=>
`c^2= a^2+b^2`

=>
`5^2= 3^2 + h^2`

=>
`h^2 = 25-9\\h^2 = 16`

Taking sqrt on both sides

=> h = 4 ft

Now, The volume:

=> Volume =
`a^2(h)/(3)`

=> Volume =
`(6)^2(4)/(3)`

=> Volume =
`36 (4)/(3)`

=> Volume = 12 * 4

=> Volume = 48 ft³