Answer:
Yes, it is true that
is a factor of
.
Explanation:
Let us try to factorize


Let us try to make a whole square of the given terms:

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Formula used above:

In the above equation, we had
.
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Further solving the above equation, taking
common out of


Taking
common out of the above term:

So, the two factors are
.
The statement that
is a factor of
is True.