Question

The focus of the parabola is: (0, -2) (2, 0) (-2, 0)

Answer 1

(-2,0)

Explanation:

1) the equation you forgot to put was x = -1/8y^2 you donut. So you multiply 8 on both sides to get 8x = -y^2. The vertices are (0,0). make 8 = 4p (from the equation to find p) and you get p=2. since it's -y^2, it's negative so you're gonna go two to the left from the vertices which is (0,0) to find focus. so the focus is gonna be (-2,0).

2) I did the odyssey ware assignment

3) I'm right cuz I said so

Answer 2

the answer is given below

Explanation:

The question is not complete, I would show you how to find the focus of a parabola when given an equation.

A parabola is the locus of a point in which its distance from a fixed point (focus) and a fixed line (directrix) is equal.

The general equation of a parabola in vertex form is given by:

y = a(x - h)² + k

The vertex is (h, k) and the focus is
`(h,k+(1)/(4)a )`

For example given an equation: 4y = (x - 3)²

4y = (x - 3)²

First we need to divide through by 4, this gives:

4y/4 = (x - 3)²/4

y = (x - 3)²/4

Comparing with The general equation of a parabola in vertex form is given by:

y = a(x - h)² + k

The vertex = (h, k) = (3, 0), the focus is
`(h,k+(1)/(4)a )` = (3, 1/16)