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Find the x-intercepts for the parabola defined by this equation

Find the x-intercepts for the parabola defined by this equation-example-1

2 Answers

1 vote

Answer:

The coordinates are (5 ,0) and (1 ,0)

Answer is given below with explanations.

Explanation:


to \: find \: the \: x \: intercepts \: of \: the \: parabola \: \\ defined \: by \: {x}^(2) - 6x + 5 = y \\ let \: y = 0 \\ then \\ {x}^(2) - 6x + 5 =0 \\ by \: factorization \\ (x - 5)(x - 1) = 0 \\ x - 5 = 0 \: \: (or )\: x - 1 = 0 \\ x = 5 \: \: ( or) \: x = 1

We want ti express the intercepts as two ordered pairs (y = 0)

Then the coordinates are (5 ,0) and (1 ,0)

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User Seetha
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5 votes

Answer:

Your x-intercepts are (1, 0) and (5, 0)

Explanation:

Factor out the expression:


y =x^(2) -6x +5 factors out to
y = (x-1) * (x-5)

Because this factored out form is now in intercept form, we can solve that the two intercepts are (1, 0) and (5, 0).

User Aorlinn
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