Question

Determine the number of real number solutions for the equation x^2-2x+6=0​

Answer 1

x^2 - 2x + 6 = 0

Use the quadratic formula

x= -b + or - squareroot b^2- 4 (a)(c)

all over 2a

a = 1

b = -2

c = 6

x= -(-2)+ or - squareroot (-2)^2 - 4(1)(6) x= 2 + or - squareroot of -20

all over 2 times 1 2

x= -20 <---- NO SOLUTION

Hope this helps :))