Complete Question
The complete question is shown on the first uploaded image
Answer:
The change in reduction potential is
![\Delta E^o=E^o_(cell) = 0.034 V](https://img.qammunity.org/2021/formulas/chemistry/college/1mrsqxjxuqmfzfgnnp4o97jfbh671762bx.png)
The change in standard free energy is
![\Delta G^o = -3.2805 \ KJ/mol](https://img.qammunity.org/2021/formulas/chemistry/college/vvklz6u29hj1d8jb6f38epjngvju7sc729.png)
Step-by-step explanation:
From the question we are told that
At the anode
⇔
![cytochrome \ c_1 \ (Fe^(2+)) \ \ E^o = 0.22 \ V](https://img.qammunity.org/2021/formulas/chemistry/college/haxizl7uxgwphx5jpywbe048k73dp3n1z4.png)
At the cathode
⇔
![cytochrome \ c \ (Fe^(2+)) \ \ E^o = 0.254 \ V](https://img.qammunity.org/2021/formulas/chemistry/college/dp7ksldjjktxmap8hw37ny2n8ht5xahpt3.png)
The difference in the reduction potential is mathematically represented as
![\Delta E^o = E^o_(cathode) - E^o_(anode)](https://img.qammunity.org/2021/formulas/chemistry/college/ocz5f4v8a08pyphx0xejzpt0uwfkmchaws.png)
substituting values
![\Delta E^o = 0.254 - 0.220](https://img.qammunity.org/2021/formulas/chemistry/college/yjipvjre6te7uk07echs7ymxe26bekusvh.png)
![\Delta E^o=E^o_(cell) = 0.034 V](https://img.qammunity.org/2021/formulas/chemistry/college/1mrsqxjxuqmfzfgnnp4o97jfbh671762bx.png)
The change in the standard free energy is mathematically represented as
![\Delta G^o = -n * F * E^o_(cell)](https://img.qammunity.org/2021/formulas/chemistry/college/e6t8iukav0vu7tqrm4hhpwava3w81vscyd.png)
Where F is the Faraday constant with value F = 96485 C
and n i the number of the number of electron = 1
So
![\Delta G^o = -(1) * 96485 * 0.034](https://img.qammunity.org/2021/formulas/chemistry/college/nyce0i9fkhtp7oqj768s1qgxzaeug3933t.png)
![\Delta G^o = -3.2805 \ KJ/mol](https://img.qammunity.org/2021/formulas/chemistry/college/vvklz6u29hj1d8jb6f38epjngvju7sc729.png)