Question

A car on a roller coaster starts at zero speed at an elevation above the ground of 26 m. It coasts down a slope, and then climbs a hill. The top of the hill is at an elevation of 16 m. What is the speed of the car at the top of the hill

Answer 1

14 m/s

Step-by-step explanation:

The velocity u at the ground from an elevation of 26 m is given by

`u=√(2gh) =√(2*9.8*26) \text{ m/s}`

Now, the speed of the car v at the top of the hill , which is at an elevation of 16 m can be calculated by

`v^2 =u^2-2gh= 2*9.8*26-2*9.8*16\\=2*9.8*10\\=196\\=14 \text{ m/s}`