Question

Divide: (y2−4y+6)÷(y+1).

Answer 1

Explanation:

hello

`y^2-4y+6= (y+1)^2-2y-1-4y+6=(y+1)^2-6y+5=(y+1)^2-6(y+1)+11`

so

`(y^2-4y+6)/(y+1)=y+1-6+(11)/(y+1)=y-5+(11)/(y+1)`

hope this helps