Question

A 0.15 g honeybee acquires a charge of 22 pC while flying. The electric field near the surface of the earth is typically 100 N/C , directed downward. What is the ratio of the electric force on the bee to the bee's weight

Answer 1

`1.50\ *10^(-6) }`

Step-by-step explanation:

Given

e=100 N/C

M=0.15 g

`q=\ 22\ pC\\=\ 22\ *10^(-2)`

The ratio of the electric force on the bee to the bee's weight can be determined by the following formula

`(fe)/(M*9.81)`

`(22*10^(-12\ *\ 100) )/(0.15*\ 10^(-3) *\ 9.81)`

`=\ 1.50\ *10^(-6)`