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What is the equation of the line that is parallel to the line y - 1 = 4(x + 3) and passes through the point (4, 32)?

y = 2 x + 33
y= *x+36
y = 4x - 16
y = 4x + 16

User BLP
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2 Answers

5 votes
The answer to your question is 15
User Berkcan
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3 votes

Answer:

y = 4x +16

Explanation:

The given equation is in "point-slope" form:

y -k = m(x -h) . . . . . . line with slope m through point (h, k)

The slope of the given line is m=4. This is the same slope as any parallel line.

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The line you want can be written in the same point-slope form as ...

y -32 = 4(x -4)

Rearranging, we have ...

y = 4x -16 +32 . . . . . add 32, eliminate parentheses

y = 4x +16 . . . . . . . . collect terms

User Mooga
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