Question

3. An extremely light rod 1.00 m long has a 2.00-kg mass attached to one end and a 3.00-kg mass attached to the other. The system rotates at a constant angular speed about a fixed axis perpendicular to the rod that passes through the rod 30.0 cm from the end with the 3.00-kg mass attached. The kinetic energy of the system is measured to be 100.0 J. (a) What is the moment of inertia of this system about the fixed axis

Answer 1

1.25 kg·m²

Step-by-step explanation:

Multiply each mass by the square of its distance from the center of rotation. The moment of inertia of the system is the sum of those products.

(a) I = Σ(mr²) = (3.0 kg)(0.30 m)² +(2.0 kg)(0.70 m)² = 1.25 kg·m²