Question

given the equations 9x + (3)/(4)y + 6 and 2x + (1)/(2)y=9 by what factor would you multiply the sencond equation to eliminate y and solve the system through linear combinations

Answer 1

-3/2

Explanation:

If the first equation is 9x +3/4y = 6, then the solution would look like this:

`\left(9x+(3)/(4)y\right)-(3)/(2)\left(2x+(1)/(2)y\right)=(6)-(3)/(2)(9)\\\\6x=-(15)/(2)\\\\x=-(15)/(12)=-(5)/(4)\\\\2\left(-(5)/(4)\right)+(1)/(2)y=9\ \longrightarrow\ y=2\left(9+(5)/(2)\right)=23`

An appropriate multiplier is -3/2.