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The daily profit in dollars made by an automobile

manufacturer is

P(x) = -35x2 +2,100x - 20,000

where x is the number of cars produced per shift. Find the

maximum possible daily profit.

User Dan Adams
by
4.2k points

1 Answer

1 vote

Answer:

The maximum possible daily profit is $11,500.

Explanation:

Vertex of a quadratic function:

Suppose we have a quadratic function in the following format:


f(x) = ax^(2) + bx + c

It's vertex is the point
(x_(v), f(x_(v))

In which


x_(v) = -(b)/(2a)

If a<0, the vertex is a maximum point, that is, the maximum value happens at
x_(v), and it's value is
f(x_(v))

In this question:

The maximum daily profit happens when
x_(v) cars are sold. This profit is
P(x_(v))


P(x) = -35x^(2) + 2100x - 20000

So
a = -35, b = 2100


x_(v) = -(2100)/(2*(-35)) = 30

The maximum possible daily profit is:


P(30) = -35*30^2 + 2100*30 - 20000 = 11500

The maximum possible daily profit is $11,500.

User ViruMax
by
5.0k points