Question

*Quadratic equations*

Solve
(i) (x+3)(x-4)=0
(ii) (2x-3)(x-1) =0​

Answer 1

Explanation:

hello,

ab = 0 <=> a = 0 or b = 0

so

(x+3)(x-4)=0 <=> x+3 = 0 or x-4 = 0 <=> x = -3 or x = 4

(2x-3)(x-1)=0 <=> 2x-3=0 or x-1 = 0 <=> x = 3/2 or x = 1

hope this helps