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a wheel has a constant angular acceleration of 3.0 rad/s2. during a certain 4.0s interval it turns through an angle of 120 rad. assuming that the wheel started from rest, how long has it been in motion at the start of this 4 s interval

1 Answer

4 votes

Answer:

8 s

Step-by-step explanation:

We are given that

Acceleration=
\alpha=3 rad/s^2

Time, t=4 s

Angle,
\theta=120 rad

Initial angular velocity,
\omega_0=0 rad/s

Let
\omega be the velocity at the start of this 4 s interval

We know that


\theta=\omega_0t+(1)/(2)\alpha t^2

Using the formula


120=4\omega+(1)/(2)(3)(4)^2


120=4\omega+24


120-24=4\omega


4\omega=96


\omega=(96)/(4)=24rad/s


t=(\omega-\omega_0)/(\alpha)=(24-0)/(3)=8 s

t=8 s

User Mathew Varghese
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