Question

An Isosceles triangle, with the base 48 cm, height 32 cm.

What is the length of the two equal sides? (In cm).

Answer 1

40 cm

Explanation:

Side²= (Base/2)²+height²= (48/2)²+32²= 1600

Side= √1600= 40 cm

Answer 2

The length of each side is 40 cm

Explanation:

Divide the base in half

48/2 = 24

Then use the Pythagorean theorem

a^2 + b^2 = c^2 with the 1/2 base and the height as the legs

24^2 + 32^2 = c^2

576+1024 = c^2

1600 = c^2

Take the square root

sqrt(1600) = sqrt(c^2)

40 = c

The length of each side is 40 cm