Question

To the nearest tenth, which is the perimeter of ABC. Geometry

Answer 1

23.6

Explanation:

Answer 2

23.6

Explanation:

Finding AC:

Cos 61 =
`(adjacent)/(hypotenuse)`

0.48 × 10 = Adjacent

AC = 4.8

Now, CB:

Cos 29 =
`(adjacent)/(hypotenuse)`

0.87 × 10 = CB

CB = 8.8

The perimeter:

=> 10+4.8+8.8

=> 23.6