Question

What are the roots of the quadratic equation below 3x2+15x-5=0

Answer 1

A

Explanation:

`3x^2+15x-5=0\\a = 3\\b = 15\\c = -5\\ x = -b\±\frac{\sqrt{b^(2) -4ac} }{2a} \\x = -(15)\±\frac{\sqrt{15^(2) -4(3)(-5)} }{2(3)} \\x = -15 \±(√(225+60) )/(6) \\x = -15\±(√(285) )/(6) = A`