Question

If the endpoints of AB have the coordinates A (9,8) and B(-1,-2), what is the midpoint of AB?

Answer 1

4,3

Explanation:

`(x_(1) + x_(2) )/(2) , (y_(1) + y_(2) )/(2)`

`(9-1)/(2) = (8)/(2) =4`

`(8-2)/(2) = (6)/(2) =3`

Answer 2

(4,3)

Solution,

A(9,8)------->(X1,x2)

B(-1,-2)------->(x2,y2)

Now,

`ab = ( (x1 + x2)/(2) </em></strong><strong><em>,</em></strong><strong><em>(y1 + y2)/(2) ) \\ \: \: \: \: \: = ( (9 + ( - 1))/(2) \: </em></strong><strong><em>,</em></strong><strong><em>(8 + ( - 2))/(2) ) \\ \: \: \: \: \: = ( (9 - 1)/(2) </em></strong><strong><em>,</em></strong><strong><em>\: (8 - 2)/(2) ) \\ \: \: \: = ( (8)/(2) </em></strong><strong><em>,</em></strong><strong><em>\: (6)/(2) ) \\ \: \: \: = (4 </em></strong><strong><em>,</em></strong><strong><em> 3)`

hope this helps...

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