Question

(2a^x + b^x)^2 i need help ASAP

Answer 1

4
`a^(2x)` + 4
`a^(x)`
`b^(x)` +
`b^(2x)`

Explanation:

Using the rule of exponents

`a^(m)` ×
`a^(n)` ⇔
`a^((m+n))`

Given

(2
`a^(x)` +
`b^(x)` ) = (2
`a^(x)` +
`b^(x)` )(2
`a^(x)` +
`b^(x)` )

Each term in the second factor is multiplied by each term in the first factor, that is

2
`a^(x)` (2
`a^(x)` +
`b^(x)` ) +
`b^(x)` (2
`a^(x)` +
`b^(x)` ) ← distribute both parenthesis

= 4
`a^(2x)` +2
`a^(x)`
`b^(x)` + 2
`a^(x)`
`b^(x)` +
`b^(2x)` ← collect like terms

= 4
`a^(2x)` + 4
`a^(x)`
`b^(x)` +
`b^(2x)`