Question

What is the distance between (-2 1/2, -3) and (1, -3)

A.-3 1/2 units
B.-1 1/2 units
C.1 1/2 units
D.3 1/2 units

Answer 1

• D) 3 1/2

Explanation:

d = √(x₂ - x₁)² + (y₂ - y₁)²

x₂ = 1

x₁ = - 2 1/2 = - 5/2

y₂ = - 3

y₁ = - 3

d = √( 1 + 5/2)² + (- 3 + 3)²

= √(2/2 + 5/2) + 0

= √(7/2)²

= 7/2

= 3 1/2

Answer 2

D

Explanation:

(-2 1/2, -3) = (-5/2 , -3) & (1, -3)

`Distance=\sqrt{(x_(2)-x_(1))^(2)+(y_(2)-y_(1))^(2)}\\\\ =\sqrt{(1-[(-5)/(2)])^(2)+(-3-[-3])^(2)}\\\\ =\sqrt{(1+(5)/(2))^(2)+(-3+3)^(2)}\\\\ =\sqrt{((7)/(2))^(2)} \\\\=(7)/(2)\\\\=3(1)/(2)`