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5 votes
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What is the center of the circle given by the equation (x+ 5)^2 + (y-8)^2 = 1?

2 Answers

4 votes

(-5, 8) is the answer

Explanation:

(-5,8)

User Roaa
by
7.8k points
7 votes

Answer:

(- 5, 8 )

Explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

(x + 5)² + (y - 8)² = 1 ← is in standard form

with centre (h, k ) = (- 5, 8 )

User Javier Villanueva
by
8.4k points

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