Question

As part of a physics experiment, Ming drops a baseball from the top of a 315-foot building. To the nearest tenth of a second, for how many seconds will the baseball fall? (Hint: Use the formula h = 16t^2, which gives the distance h, in feet, that a free-falling object travels in t seconds.)

Answer 1

≈ 4.44 sec

Explanation:

h= 315 ft

h= 16t²

315 = 16t²

t²=315/16

t=√315/16 ≈ 4.44 sec

Answer 2

Answer: 4.4 seconds

Explanation:

h(t) = -16t² + 315

Since we want to find the total time the baseball is in the air, we need to find the time (t) when the ball lands on the ground --> h(t) = 0

0 = -16t² + 315

-315 = -16t²

`(315)/(16)=t^2\\\\\\\sqrt{(315)/(16)}=t\\\\\\(√(315))/(4)=t\\\\\\\large\boxed{4.4=t}`