Question

An elevator filled with passengers has a mass of 1700 kg. (a) The elevator accelerates upward from rest at a rate of 1.20 m/s2 for 1.50 s. Calculate the tension in the cable supporting the elevator. (b) The elevator continues upward at constant velocity for 8.50 s. What is the tension in the cable during this time

Answer 1

Step-by-step explanation:

mass m=1700 Kg

a = 1.20 m/s^2.

t_a= 1.50 sec

According to Newton's 2nd law the net force

`F_(net) =ma`

`F_a=m(a+g)=1700(1.2+9.80)=1.87*10^4 N`

now,

`F_(net) =0\\F_b= W =1700*9.8 =1.67*10^4 N`