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find the mass of h2 produced Binary compounds of alkali metals and hydrogen react with water to produce H2(g). The H2H2 from the reaction of a sample of NaH with an excess of water fills a volume of 0.505 L above the water. The temperature of the gas is 35 ∘C∘C and the total pressure is 755 mmHg

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Answer: Mass of hydrogen produced is 0.0376 g.

Step-by-step explanation:

The reaction equation will be as follows.


NaH(aq) + H_(2)O(l) \rightarrow H_(2)(g) + NaOH(aq)

Now, formula for total pressure will be as follows.


P_(total) = P_{H_(2)} + P_{H_(2)O}

Hence,
P_{H_(2)} = P_(total) - P_{H_(2)O}

= 755 mm Hg - 42.23 mm Hg

= 712.77 mm Hg


P_{H_(2)} = (712.77 * 1 atm)/(760 mm Hg)

= 0.937 atm

Now, we will calculate the moles of
H_(2) as follows.


P_{H_(2)}V = nRT


0.937 atm * 0.505 L = n * 0.0821 * 308.15 K

n =
(0.473)/(25.29) mol

= 0.0187 mol

Therefore, mass of
H_(2) will be calculated as follows.


m_{H_(2)} = (0.0187 mol * 2.0158 g)/(1 mol)

= 0.0376 g

Thus, we can conclude that mass of hydrogen produced is 0.0376 g.

User Dziwna
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