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a softball player moving 3.89 m/s starts a slide, decelerating at -1.44 m/s^2 for 4.80 m. how much time does the slide take? (she does not come to a stop)

1 Answer

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Step-by-step explanation:

We have,

Initial speed of a softball is 3.89 m/s

Deceleration of the ball is -1.44 m/s²

Distance covered by the ball is 4.8 m

It is required to find the time that the ball take when it slides. Let t is time. Using second equation of motion :


h=ut+(1)/(2)at^2

Putting all the values we get :


4.8=3.89t+(1)/(2)(-1.44)t^2\\\\4.8=3.89t-0.72t^2\\\\t=1.9\ s \ \text{and}\ t=3.49\ s

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