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Me pueden ayudar en esta ecuación bicuadratica, porfaaa: 9p⁴=—12x²—6/9

User Modermo
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1 Answer

1 vote

Answer:

x = -1.129i, -0.241i, 0.241i o 1.129i.

Tenga en cuenta que i = √(-1), i es el representante de un número complejo.

x = -1.129i, -0.241i, 0.241i or 1.129i.

Note that i = √(-1), i is the representative of a complex number.

Explanation:

Pregunta correcta

¿Me pueden ayudar en esta ecuación biquadratica, por favor: 9x⁴ = —12x² - 6/9

Solución

9x⁴ = —12x² - 6/9

9x⁴ + 12x² + 6/9 = 0

multiplicar por 9

81x⁴ + 108x² + 6 = 0

Deje x² = y, entonces x⁴ = y²

81y² + 108y + 6 = 0

Resolviendo esta ecuación cuadrática

y = -0.0581 o y = -1.275

Recordemos, x² = y

x = ±√y

Si y = -0.0581

x = ± √(-0.0581) = ± 0.241i = 0.241i o -0.241i

Si y = -1.275

x = ± √(-1.275) = ± 1.129i = 1.129i o -1.129i

x = -1.129i, -0.241i, 0.241i o 1.129i.

Tenga en cuenta que i = √(-1), i es el representante de un número complejo.

¡¡¡Espero que esto ayude!!!

Correct Question

Can you help me in this biquadratic equation, please: 9x⁴ = —12x² — 6/9

Solution

9x⁴ = —12x² — 6/9

9x⁴ + 12x² + 6/9 = 0

multiply through by 9

81x⁴ + 108x² + 6 = 0

Let x² = y, then x⁴ = y²

81y² + 108y + 6 = 0

Solving this quadratic equation

y = -0.0581 or y = -1.275

Recall, x² = y

x = ±√y

If y = 0.0581

x = ±√(-0.0581) = ±0.241

If y = -1.275

x = ± √(-1.275) = ± 1.129i = 1.129i or -1.129i

Hence x = -1.129i, -0.241i, 0.241i or 1.129i.

Note that i = √(-1), i is the representative of a complex number.

Hope this Helps!!

User Fyasir
by
8.4k points
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