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2 votes
Tony has $20. He wants to buy at least 4

snacks. Hot dogs (x) are $3 each.
Peanuts (y) are $2 each.​

2 Answers

3 votes

Answer:

4 is the first one and the second one is ---->

Total Price: 3x + 2y ≤ 20

Explanation:

Let's complete the inequalities that represent Tony's situation.

Given:

Tony wants to buy at least 4 snacks.

Hot dogs (x) are $3 each.

Peanuts (y) are $2 each.

We can form the following inequalities:

Total Snacks: Tony wants to buy at least 4 snacks, which can be represented by the inequality:

x + y ≥ 4

This inequality ensures that the sum of hot dogs (x) and peanuts (y) is greater than or equal to 4, indicating that Tony wants to buy at least 4 snacks in total.

Total Price: To represent the total price, we need to consider the cost of each snack. Hot dogs are $3 each, and peanuts are $2 each. Thus, the total price can be represented by the inequality:

3x + 2y ≤ 20

This inequality accounts for the total cost of the snacks Tony wants to buy. The left-hand side represents the cost of x hot dogs ($3 each) and y peanuts ($2 each), and the inequality ensures that the total cost does not exceed Tony's available budget of $20.

Therefore, the completed inequalities are:

Total Snacks: x + y ≥ 4

User Cammy
by
3.5k points
2 votes

Tony has $20. He wants to buy at least 4

snacks. Hot dogs (x) are $3 each.

Peanuts (y) are $2 each.​

Answer:

To solve the above question, we use the below inequality equations

x + y ≥ 4 snacks .........Inequality equation 1

3x + 2y ≤ $20 ..........Inequality equation 2

Explanation:

We can make use of the inequality equations

Hot dogs = (x) are $3 each.

Peanuts = (y) are $2 each.​

He wants to buy at least 4

x + y ≥ 4 snacks .........Inequality equation 1

3x + 2y ≤ $20 ..........Inequality equation 2

From the above inequality equations, Tony can buy at least 4 snacks but he can only spend $20.

Let take a random number, where x = 4, and y = 4. This means Tony can buy

a) 4($3) + 4($2) = 12 + 8 = $20

The total number of snacks = 4 + 4 = 8 snacks.

b)

This answer above confirms the inequality equations 1 and 2

x + y ≥ 4 snacks .........Inequality equation 1

8 snacks ≥ 4 snacks

3x + 2y ≤ $20 ..........Inequality equation 2

$20 ≤ $20

User Abhay Saraf
by
3.1k points