Question

Write the equation of the line perpendicular to y= 5/4x+9/4

that passes through the point (-8,7). Write the equation using slope-intercept form or using the given in point-slope form.

Answer 1

Explanation:

`y= 5/4x+9/4\\ (-8,7).\\\\m = (5)/(4) \\\\Perpendicular =m= (1)/(m2)\\\ 5/4 = -4/5\\substitute : (-8,7)-into slope -intercept -form\\ \\y =mx+b\\7=(-4)/(5)(-8)+b\\\\7 = (32)/(5) +b\\\\b=7-32/5\\b = 3/5\\m =-4/5\\substitute-into-slope-intercept-form\\y = mx+b\\y = -(4)/(5) x+(3)/(5)\\`

Answer 2

`x = (4y - 9)/(5)`

`(5)/(4x) + (9)/(4) = y \\ (5)/(4x) = y - (9)/(4) \\ (5)/(4) over (5)/(4x) = \frac{y - (9)/(4) }{5 \frac{}{4} } \\ x = (4y - 9)/(5)`