Question

An uniform electric field of magnitude E = 100 N/C is oriented along the positive y-axis. What is the magnitude of the flux of this field through a square of surface area A = 2 m2 oriented parallel to the yz-plane? Group of answer choices

Answer 1

∅ = 0 V.m

Step-by-step explanation:

The electric flux through a surface is given by the following formula:

∅ = E.ΔA

∅ = E ΔA Cosθ

where,

∅ = Electric Flux through the surface = ?

E = Electric Field Intensity = 100 N/C

ΔΑ = Surface Area = 2 m²

θ = Angle between the electric field and the the normal area vector

The electric field is oriented in positive y-axis direction. The surface is parallel to yz-plane, so its normal area vector will be in the direction of x-axis. Therefore, the electric field and normal area vector shall be perpendicular to each other. Therefore,

θ = 90°

Using values in the equation:

∅ = (100 N/C)(2 m²)(Cos 90°)

∅ = (200 N.m²/C)(0)

∅ = 0 V.m