Question

A painter leans a 10 ft ladder against a building.

The base of the ladder is 7 ft from the building.
To the nearest foot, how high on the building
does the ladoer reach?

Answer 1

7.14 ft

I hope it helps :)

Explanation:

`Hypotenuse = 10\\Opposite = 7\\Adjacent = x\\ \\Using Pythagoras theorem ;\\Hyp^(2) =opp^(2) +adj^(2) \\10^(2) = 7^(2) +x^(2) \\100 = 49+x^(2) \\x^(2) =100-49\\x^(2) =51\\\sqrt{x^(2) } =√(51) x = 7.14 ft`