Question

David is throwing a stone in the air at an angle from the ground with an initial velocity of 30 feet per second. The equation gives the height of the stone thrown. Find the maximum height of the stone.

(SHOW WORK)

Answer 1

42 feet.

Explanation:

h=-10t² + 40t +2

The vertex of the quadratic function described by the equation is located at

t = -(40)/(2(-10)) = 2

Next is to find the value of height at t=2 will be

h = -10(2²) +40(2) +2 = -40 +80 +2 = 42feet

The maximum height is 42 feet.