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2+5∛x = 32 Find the value of X

User Skroczek
by
5.3k points

1 Answer

6 votes

Answer:

x = 216

Explanation:

2 + 5
\sqrt[3]{x} = 32

Subtract 2 from both sides of the equation

i.e. 2 + 5
\sqrt[3]{x} - 2 = 32 - 2

5
\sqrt[3]{x} = 30

Take the cube of both sides of the equation

i.e. (5
\sqrt[3]{x})³ = (30)³

(5)³(
\sqrt[3]{x})³ = (30)³

(5 × 5 × 5)(
\sqrt[3]{x})³ = (30 × 30 ×30)

125x = 27,000

Divide both sides of the equation by the coefficient of x(which is 125)


(125x)/(125) = (27000)/(125)

x = 216

Check

Substituting 216 for x in 2 + 5∛x = 32,

2 + 5
\sqrt[3]{216} = 32 (
\sqrt[3]{216} = 6)

2 + (5 × 6) = 32

2 + 30 = 32

∴ x = 216

Hope this helps :))

User HABJAN
by
5.3k points