Question

A firework rocket consists of a cone stacked on top of a cylinder where the radius of the cone and the cylinder are equal the diameter of the cylindrical base of the rocket is 8 in and the height of the cylinder is 5 in while the height of the cone is 3 in

Answer 1

Surface area of the rocket = 76π

Explanation:

Given:

Diameter = 8 in

Radius of cylinder = 4 in

Radius of cone = 4 in

Height of the cylinder = 5 in

Height of the cone = 3 in

Find:

Surface area of the rocket.

Computation:

Slant hight =
`√(4^2 + 3^2)`

Slant hight = 5 in

Surface area of the rocket = Surface area of cylinder + Surface area of cone + Area of circle

Surface area of the rocket = 2πrh + πrl + πr²

Surface area of the rocket = 2π(4)(5) + (π)(4)(5) + (π)(4)²

Surface area of the rocket = 40π + 20π + 16π

Surface area of the rocket = 76π