Question

the temperature of a sample of water increases from 20celsius to 46.6celsius as it absorbs 5650 J of heat. what is the mass of the sample?

Answer 1

m = 50.74 kg

Step-by-step explanation:

We have,

Initial temperature of water is 20 degrees Celsius

Final temperature of water is 46.6 degrees Celsius

Heat absorbed is 5650 J

It is required to find the mass of the sample. The heat absorbed is given by the formula ad follows :

`Q=mc\Delta T`

c is specific heat of water, c = 4.186 J/g°C

So,

`m=(Q)/(c\Delta T)\\\\m=(5650)/(4.186* (46.6-20))\\\\m=50.74\ kg`

So, the mass of the sample is 50.74 kg.