Answer:
112.3 square units
Explanation:
Find the sketch of the triangle attached.
Area of the triangle =
Given PQ = 20, PR = 12 and ∠QPR = 68°
Area of the triangle = 1/2 * 20 * 12 * sin68°
Area of the triangle = 120sin68°
Area of the triangle = 112.26 square units
Area of the triangle ≈ 112.3 square units (to the nearest tenth of a square unit)