Question

Zohar is using scissors to cut a rectangle with a length of 5x – 2 and a width of 3x + 1 out of a larger piece of paper. Which expression can be used to find the perimeter of the rectangle and what is the perimeter if x = 4? (5x−2)+(3x+1); 31 centimeters (5x−2)+(3x+1); 36 centimeters 2(5x−2)+2(3x+1); 62 centimeters 2(5x−2)+2(3x+1); 70 centimeters

Answer 1

C

Explanation:

edge2020

Answer 2

`\boxed{\sf Perimeter \ of \ rectangle = 2(5x - 2) + 2(3x + 1); 62 \ centimeters}`

Given:

Length of rectangle (l) = (5x - 2) cm

Width of rectangle (w) = (3x + 1) cm

To Find:

Perimeter of rectangle

Explanation:

`\sf \boxed{\sf Perimeter \ of \ rectangle = 2(length + width)} \\ \\ \sf Putting \ value \ of \ length \ and \ with \ in \ the \\ \sf formula \ of \ perimeter \ of \ rectangle, \ we \ get:\\ \sf = 2((5x - 2) + (3x + 1)) \\ \\ \sf = 2(5x - 2) + 2(3x + 1)`

`\sf Now, \ let's \ find \ the \ value \ of \ perimeter \ of \\ \sf rectangle \ by \ substituting \ x = 4, \ we \ get: \\ \\ \sf Perimeter \ of \ rectangle = 2(5(4) - 2) + 2(3(4) + 1) \\ \\ \sf 5 * 4 = 20 : \\ \sf = 2( \boxed{20} - 2) + 2(3(4) + 1) \\ \\ \sf 3 * 4 = 12 : \\ \sf = 2(20 - 2) + 2( \boxed{12} + 1) \\ \\ \sf 20 - 2 = 18 : \\ \sf = 2 * \boxed{18} + 2(12 + 1) \\ \\ \sf 12 + 1 = 13 : \\ \sf = 2 * 18 + 2 * \boxed{13} \\ \\ \sf 2 * 18 = 36 : \\ \sf = \boxed{36} + 2 * 13 \\ \\ \sf 2 * 13 = 26 : \\ \sf = 36 + \boxed{26} \\ \\ \sf = 62 \: centimeters`