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Subtract. 2x+3x−6−x2+x−1x2−5x−6 x2+4x+2(x−6)(x−1) (x+2)2(x−6)(x+1) x2+6x+2(x−6)(x+1) (x+2)2(x−6)(x−1)

User Zegarek
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1 Answer

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Answer: To subtract the given expression, let's simplify and combine like terms.

First, let's simplify the numerator of the expression:

2x + 3x - 6 - x^2 + x - 1

= (2x + 3x + x) + (-6 - 1) - x^2

= 6x - 7 - x^2

Now, let's simplify the denominator of the expression:

x^2 + 4x + 2(x - 6)(x - 1)

= x^2 + 4x + 2(x^2 - 7x + 6)

= x^2 + 4x + 2x^2 - 14x + 12

= 3x^2 - 10x + 12

Finally, let's divide the numerator by the denominator:

(6x - 7 - x^2) / (3x^2 - 10x + 12)

At this point, we cannot simplify the expression further. Therefore, the subtraction of the given expression is:

(6x - 7 - x^2) / (3x^2 - 10x + 12)

User Rigotre
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