Question

PLEASE HELP IMAGE ATTACHED!!

Answer 1

Explanation:

Parallel lines have same slope

19) y = x - 4

m = 1 ; (2, 3 )

Equation: y - y₁ = m(x- x₁)

y - 3 = 1(x - 2)

y - 3 = x -2

y = x - 2 + 3

y = x + 1

20) 2x + 3y = 3

We have to write in y = mx + b form

3y = - 2x - 3

`y=(-2)/(3)x-(3)/(3)\\\\y=(-2)/(3)x-1\\\\m=(-2)/(3)`; (-6, -1)

`y-[-1]=(-2)/(3)(x-[-6])\\\\y+1=(-2)/(3)(x+6)\\\\y+1=(-2)/(3)x+(-2)/(3)*6\\\\y+1=(-2)/(3)x-4\\\\y=(-2)/(3)x-4-1\\\\y=(-2)/(3)x-5`

for perpendicular lines, m2 = -1/m1

21) y = 2x+ 5

m1 = 2

`m_(2)=(-1)/(2)`; (-2,8)

`y-8=(-1)/(2)(x-[-2])\\\\y-8=(-1)/(2)(x+2)\\\\y-8=(-1)/(2)x+2*(-1)/(2)\\\\y-8=(-1)/(2)x-1\\\\y=(-1)/(2)x-1+8\\\\y=(-1)/(2)x+7`

22) x+ 4y = 8

4y = -x + 8

`y=(-1)/(4)x+(8)/(4)\\\\y=(-1)/(4)x+2\\\\m_1=(-1)/(4)\\\\m_(2)=4\\\\`

m2 = 4; (-2,-11)

y - [-11] = 4(x -[-2])

y + 11 = 4 (x + 2)

y + 11 = 4x + 8

y = 4x + 8 - 11

y = 4x - 3