Question

Applying the recursive rule aₙ; a ₙ ₋ ₁ + 3, write the first seven (7) terms of the sequence when a = 10.

Answer 1

First seven terms apart from 10 are

13, 16, 19, 22, 25, 28, 31

Explanation:

Given recursive rule aₙ = a ₙ ₋ ₁ + 3

a1 = 10

`x_(1) = 10\\x_(2) = x_(2-1) + 3= x_(1) + 3 = 10 + 3 = 13\\x_(3) = x_(3-1) + 3= x_(2) + 3 = 13 + 3 = 16\\x_(4) = x_(4-1) + 3= x_(3) + 3 = 16 + 3 = 19\\x_(5) = x_(5-1) + 3= x_(4) + 3 = 19 + 3 = 22\\x_(6) = x_(6-1) + 3= x_(5) + 3 = 22 + 3 = 25\\\x_(7) = x_(7-1) + 3= x_(6) + 3 = 25 + 3 = 28\\x_(8) = x_(8-1) + 3= x_(7) + 3 = 28 + 3 = 31`

Thus, first seven terms apart from 10 are

13, 16, 19, 22, 25, 28, 31