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Solve the following system by of linear equation by guass jordan method 2x+2y+4z=18 X+3y+2z=13 3x+2y-3z=14
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Solve the following system by of linear equation by guass jordan method 2x+2y+4z=18 X+3y+2z=13 3x+2y-3z=14

User Xcecution
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Answer:


x + 3y + 2z = 13 \\ 2x + 2y + 4z = 18 \\ 3x + 2y - 3z = 14 \\ \\ x = - 3y - 2z + 13 \\ 2( - 3y - 2z + 13) + 2y + 4z = 18 \\ 3( - 3y - 2z + 13) + 2y - 3z = 14 \\ y = 2 \\ z = (25)/(9) - (7)/(9) y \\ z = (25)/(9) - (7)/(9) * 2 \\ z = (11)/(9) \\ x = - 3 * 2 - 2( (11)/(9) ) + 13 \\ x = (41)/(9) \\ y = 2 \\ z = (11)/(9)

User Nico Zhu
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