85.7k views
3 votes
Write the equation for the perpendicular bisector of a segment that has endpoints (–1, 10) and (3, 6).

2 Answers

2 votes

Question:

Write the equation for the perpendicular bisector of a segment that has endpoints (–1, 10) and (3, 6).

Question 11 options:

A) y = x + 7

B) y = –x + 9

C) y = x + 11

D) y = x – 7

Answer:

the answer is B) y=-x+9

Step by Step Explanation:


m= (y_(2) - y_(1))/(x_(2) - x_(1)) = (6-10)/(3+1)=(-4)/(4) = -1\\m= -1\\\\y=mx +b\\y = -x +b\\6=-1(3) +b\\6= -3+b\\6+3 = b\\9=b\\\\y=-x+9

User Ugnes
by
5.3k points
5 votes

Answer:

I think it is -4=4x+10

Explanation:

6-10=-4

.......

3-(-1)=4

......

y=mx+b

......

-4=4x+10

User Fedd
by
4.9k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.