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What is the true solution to 2 In e^in5x – 2 In 15?

1 Answer

6 votes

Answer:
\bold{\ln \bigg((x^2)/(9)\bigg)}

Explanation:


2\ln e^(\ln(5x))-2\ln 15\\\\\\= \ln (e^(\ln(5x)))^2-2\ln 15\\\\\\= \ln(5x)^2-ln(15)^2\\\\\\= \ln\bigg(((5x)^2)/((15)^2)\bigg)\\\\\\= \ln\bigg((25x^2)/(225)\bigg)\\\\\\=\large\boxed{\ln \bigg((x^2)/(9)\bigg)}

User Saeed Mohtasham
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