Answer:
![a.\ P(x) = - 0.002x^2+3.8x-40](https://img.qammunity.org/2021/formulas/mathematics/college/s1kys5ey8n9x4qbafziicrkdwvup95uhkh.png)
b. 320
![c.\ P'(x) = -0.004 x + 3.8](https://img.qammunity.org/2021/formulas/mathematics/college/aqmd8zki782yq6czp3mw7pm8pcohlad28s.png)
d. 3.76
Explanation:
Given that:
Revenue function:
![R(x) = 6x](https://img.qammunity.org/2021/formulas/mathematics/college/mqco1jl41prsjy607f6kvsahm2sl3kd2w8.png)
Cost Function:
![C(x) = 0.002x^2+2.2x+40](https://img.qammunity.org/2021/formulas/mathematics/college/wmpjwwr1wuexl5jvdz8eo982e78vw5vbys.png)
We know that,
Answer a: Profit = Revenue - Cost
![\Rightarrow P(x) = R(x) - C(x)\\\Rightarrow P(x) = 6x - (0.002x^2+2.2x+40)\\\Rightarrow P(x) = - 0.002x^2+3.8x-40](https://img.qammunity.org/2021/formulas/mathematics/college/5oa48z4u7v3fpaifg3iyhxtv5j5eo5eo2e.png)
Answer b:
P(100) = ?
Putting value of x as 100 in above equation:
![P(100) = - 0.002* 100^2+3.8 * 100-40\\\Rightarrow P(100) = -20+380 -40\\\Rightarrow P(100) = 320](https://img.qammunity.org/2021/formulas/mathematics/college/he6tpbthokab8vr888m7tfyxgutc28djwo.png)
Answer c:
P'(x) = ?
Differentiating the equation
![P(x) = - 0.002x^2+3.8x-40](https://img.qammunity.org/2021/formulas/mathematics/college/isfr3enpa8yqgjnqqckijcg0e0kqd9l378.png)
![P'(x) = -2 * 0.002 x^(2-1) + 3.8 + 0\\P'(x) = -0.004 x + 3.8](https://img.qammunity.org/2021/formulas/mathematics/college/ekgyendr7t74ihy3msjsv31ok5lw9v3k36.png)
Answer d:
P'(100) = ?
Putting x = 100 in equation
![P'(x) = -0.004 x + 3.8](https://img.qammunity.org/2021/formulas/mathematics/college/7ggzlc6gv03mh3ywd9ier3kmse7l3adtew.png)
![P'(100) = -0.004 * 100 + 3.8\\P'(100) = -0.4 + 3.8\\P'(100) = 3.76](https://img.qammunity.org/2021/formulas/mathematics/college/hykw2fmr6ii4ud6bf60dvz2scy72lvt8bh.png)