Question

Find the equation of the straight line passing through the point (0, 1)

which is perpendicular to the line
y = -2x + 2
:)

Answer 1

y = \frac{1}{2} x+1

Explanation:

Answer 2

`y = (1)/(2) x+1`

Explanation:

Perpendicular => So, it will have a slope of a negative reciprocal to this slope

Slope = m = 1/2

Now,

Point = (x,y) = (0,1)

So, x = 0 and y = 1

Putting this in slope-intercept equation to get b

=>
`y = mx+b`

=> 1 = (1/2)(0) + b

=> b = 1

Now putting m and b in the slope intercept equation to get the required equation

=>
`y = (1)/(2) x+1`